Question

X intercept f(x)=(x+4)^2

Answer 1

-4

Explanation:

Given the function f(x)=(x+4)², the x intercept occurs at f(x) = 0, substituting f(x) = 0 into the given equation to get the value of x we have;

`0 = (x+4)^(2) \\`

Taking the square root of both sides

`√((x+4))^(2) = √(0)\\ x+4 = 0\\`

Subtracting 4 from both sides of the equation

`x+4-4 = 0-4\\x = -4`

Therefore the x intercept of the equation is -4