Question

A Calculate the volume of a substance present in 1.505 x10^23 atoms of sulphur (iv) oxide at stp.​

Answer 1

5.597 liters SO2 at STP

Step-by-step explanation:

1 mole is 6.023 x 10^23 items, in this case sulfur dioxide (SO2). 1.505x10^23 represents:

(1.505x10^23 atoms SO2/6.023 x 10^23 atoms SO2/mole SO2) or 0.250 moles of SO2. The molar mass of SO2 is 64.1 grams/mole. But the question is what volume, not what mass. The volume of any gas at STP can be determined using a handy conversion factor. All gasses at STP occupy 22.4 moles for every liter. We have 0.250 moles SO2, so we'll have:

(0.250 moles)*(22.4 Liters/mole) = 5.597 liters SO2