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A Michelson interferometer operating at a 400 nm wavelength has a 3.95-cm-long glass cell in one arm. To begin, the air is pumped out of the cell and mirror M2 is adjusted to produce a bright spot at the center of the interference pattern. Then a valve is opened and air is slowly admitted into the cell. The index of refraction of air at 1.00 atmatm pressure is 1.00028.

Required:
How many bright-dark-bright fringe shifts are observed as the cell fills with air?

User Aleksandra
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1 Answer

3 votes

Answer:

55.3

Step-by-step explanation:

The computation of the number of bright-dark-bright fringe shifts observed is shown below:


\triangle m = (2d)/(\lambda) (n - 1)

where

d =
3.95 * 10^(-2)m


\lambda = 400 * 10^(-9)m

n = 1.00028

Now placing these values to the above formula

So, the number of bright-dark-bright fringe shifts observed is


= (2 *3.95 * 10^(-2)m)/(400 * 10^(-9)m) (1.00028 - 1)

= 55.3

We simply applied the above formula so that the number of bright dark bright fringe shifts could come

User Leitasat
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