Question

A steel cylindrical pressure vessel has an inside diameter of 2m and a wall thickness of 2cm. If the steel has a yield stress Y= 425 MPa, calculate the tank pressure that would just cause yielding of the tank material:

Answer 1

The pressure that will cause yielding in the tank in the longitudinal direction is 1.7 Mpa

Step-by-step explanation:

We are dealing with a thin-walled pressure vessel here.

the formula for calculating the hoops stress of this pressure vessel is
`\sigma =P d/4t`

`\sigma Y =` longitudinal yield stress =
`425 * 10^(6) Pa`

Thickness = 2/1000 =0.002m

Outside diameter = inside siameter + thickness = 2m + 0.002m= 2.002m

Dm = Mean diameter = Outside diameter - thickness = 2.002 - 0.002 = 2m

`P= 425 * 10^(6) * 4 * 0.002 /2=1.7 Mpa`