Question

Find the maximum/minimum value of the quadratic function g^2-2g=y+323 by completing the sqaure method

Answer 1

the minimum value of y is -324

Explanation:

Add the square of half the g coefficient:

g^2 -2g +1 = y +324

(g -1)^2 -324 = y

This is "vertex form" indicating the vertex is (1, -324). The leading coefficient is positive, so the parabola opens upward. The vertex is the minimum.

Minimum y-value is -324.