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Complete the proof to show that ABCD is a parallelogram. On a coordinate plane, quadrilateral A B C D is shown. Point A is at (negative 2, negative 2), point B is at (negative 3, 4), point C is at (2, 2), and point D is at (3, negative 4). The slope of Line segment B C is StartFraction 4 minus 2 Over negative 3 minus 2 EndFraction = negative two-fifths The slope of Line segment A D is StartFraction negative 4 minus (negative 2) Over 3 minus (negative 2) EndFraction = StartFraction negative 4 + 2 Over 3 + 2 EndFraction = negative two-fifths The slope of Line segment C D is StartFraction 2 minus (negative 4) Over 2 minus 3 EndFraction = StartFraction 2 + 4 Over 2 minus 3 EndFraction = StartFraction 6 Over negative 1 EndFraction = negative 6 The slope of Line segment B A is StartFraction 4 minus (negative 2) Over negative 3 minus (negative 2) EndFraction = StartFraction 4 + 2 Over negative 3 + 2 EndFraction = StartFraction 6 Over negative 1 EndFraction = negative 6 and because the ________________________________. Therefore, ABCD is a parallelogram because both pairs of opposite sides are parallel.

2 Answers

3 votes

Answer:

c.) on edg.

Explanation:

got it right :)

User Kadir Erdem Demir
by
7.9k points
1 vote

Answer:

Slopes of parallel lines are equal

Explanation:

On a coordinate plane, quadrilateral ABCD is shown. Point A is at (-2, -2), point B is at (-3, 4), point C is at (2, 2), and point D is at (3, -4).

The slope of the line segment BC is:


(4-2)/(-3-2) =-(2)/(5)

The slope of the line segment AD is:


(-4-(-2))/(3-(-2)) =(-4+2)/(3+2)=-(2)/(5)

The slope of the line segment CD is:


(2-(-4))/(2-3) =(2+4)/(2-3)=(6)/(-1)=-6

The slope of the line segment BA is:


(4-(-2))/(-3-(-2)) =(4+2)/(-3+2)=(6)/(-1)=-6

Because the slopes of parallel lines are equal. Therefore, ABCD is a parallelogram because both pairs of opposite sides are parallel.

User Alexandre Hamon
by
7.5k points

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