Question

(5372 + 100y^2) + 5(10y^2 – 110) Add the two polynomials and write in the form ay^2 + b, where a and b are constants, What is the value of a + b?

Answer 1

The value of a is 150 and b is 4822.

Step-by-step explanation:

First, you have to expand to remove brackets :

`(5372 + 100 {y}^(2) ) + 5(10 {y}^(2) - 110)`

`= 5372 + 100 {y}^(2) + 50 {y}^(2) - 550`

Next, you have to simplify :

`100 {y}^(2) + 50 {y}^(2) + 5372 - 550`

`= 150 {y}^(2) + 4822`

Next, you have to compare it :

`a {y}^(2) + b = 150 {y}^(2) + 4822`

`a = 150`

`b = 4822`