Question

Find the 11th term from the end of the A.P 10,7,4.... -62.​

Answer 1

Term 11=a+10d

Here

a=10

d= 7-10= -3

Term 11;

=10+(10×-3)

=10+(-30)

= -20 is the answer

Thank you Hope it helps dear

Answer 2

Answer: -32

Explanation:

a=10, d = 7-10 = -3

First find which term is -62

an = -62

a = (n-1) d= -62

Putting values

10 + (n-1)(-3) = -62

10 + (n(-3) -1 (-3) = -62

10 - 3n + 3 = -62

13 - 3n = -62

-3n = -62-13

n = 75/3 = 25

We need to find out 11th term from the last term ie., 25 - 10 = 15th term

So we need to find a14

an = a +(n-1) d

a15 = 10+ (15-1) (-3)

= 10 + 14 (-3)

= 10 -42

= -32

So the 11th term from the 15th term from the first = -32