1.9k views
5 votes
Find the 11th term from the end of the A.P 10,7,4.... -62.​

User ErvalhouS
by
7.9k points

2 Answers

5 votes

Term 11=a+10d

Here

a=10

d= 7-10= -3

Term 11;

=10+(10×-3)

=10+(-30)

= -20 is the answer

Thank you Hope it helps dear

User NicholasFolk
by
8.3k points
4 votes

Answer: -32

Explanation:

a=10, d = 7-10 = -3

First find which term is -62

an = -62

a = (n-1) d= -62

Putting values

10 + (n-1)(-3) = -62

10 + (n(-3) -1 (-3) = -62

10 - 3n + 3 = -62

13 - 3n = -62

-3n = -62-13

n = 75/3 = 25

We need to find out 11th term from the last term ie., 25 - 10 = 15th term

So we need to find a14

an = a +(n-1) d

a15 = 10+ (15-1) (-3)

= 10 + 14 (-3)

= 10 -42

= -32

So the 11th term from the 15th term from the first = -32

User Tommy Steimel
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories