174k views
0 votes
Find the oxidation number of chromium in K2Cr2O7​

User Brrwdl
by
7.2k points

1 Answer

7 votes

Answer:

The oxidation state of chromium is +6

Step-by-step explanation:

Let the oxidation number be x

Since The sum of all oxidation numbers are equal to zero,

So,

(+1)2 + 2x + (-2)7 = 0

+2 +2x -14 = 0

2x-12 = 0

2x = +12

Dividing 2 to both sides

x = +6

User Eitann
by
7.1k points