Question

Given: AC and BD are diameters. If chord CD is drawn, the measure of angle ACD would be

Answer 1

Explanation:

1=78°

3= 78°

4= 360°- 78° - 78°

= 204° ÷ 2

= 102°

2= 102°

Note that 1+2+3+4=360°

180° - (4)

= 180° - 102°

= 78° ÷ 2

= 39°

ans; angle ACD is 39°

Answer 2

39°

Explanation:

Both ∠ACD and ∠1 refer to same arc AD

Since ∠1 is central angle, it is the twice the size of ∠ACD,

therefore

• ∠ACD= ∠1/2= 78°/2= 39°