Answer:'3^14
Explanation:
This geometric sequence has common ratio 3 and first term 1.
Thus, the general formula for the nth term is a(n) = 1*3(n - 1).
The 15th term is thus a(15) = 1*3^(n -1) = 3^14.
Answer:
a₁ = 1
r = 3/1 = 3
an = a₁rⁿ⁻¹
a₁₅ = 1*(3)¹⁴
a₁₅ = 4782969
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