Answer:
The distance between points P and Q on this campus map of the local college is 13.038 units
Explanation:
We are given that Joanne does a daily walk from building P to building Q

We are supposed to find the distance between points P and Q on this campus map of the local college
We will use distance formula :

Substitute the values in the formula .

Hence the distance between points P and Q on this campus map of the local college is 13.038 units