Answer:
The distance between points P and Q on this campus map of the local college is 13.038 units
Explanation:
We are given that Joanne does a daily walk from building P to building Q
![P=(x_1,y_1)=(6,9)\\Q = (x_2,y_2)=(5,-4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/z71dy1udteb1vpgjha1iqi9ebwl90a87pb.png)
We are supposed to find the distance between points P and Q on this campus map of the local college
We will use distance formula :
![d = √((x_2-x_1)^2+(y_2-y_1)^2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/dqbsqwgrrgc21cw3vr7fydj59bcru5qpz8.png)
Substitute the values in the formula .
![d=√((5-6)^2+(-4-9)^2)\\d=13.038](https://img.qammunity.org/2021/formulas/mathematics/high-school/o1pp4bp5qd4brc24x43sv7ybixysn5y2aw.png)
Hence the distance between points P and Q on this campus map of the local college is 13.038 units