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Question one answer: S²=3V/H

What is the opposite operation of squaring? Using this opposite operation, rewrite the equation from question 1 so s is by itself on one side of the equation.


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Answer:


\ S=\sqrt{(3V)/(H)}}

Explanation:

The opposite operation of squaring is taking the square root.


\ S=\sqrt{(3V)/(H)}}

We know that the denominator of a fractional power is the index of the corresponding root:


\displaystyle x^(1)/(n)=\sqrt[n]{x}

For n=2, we don't usually write the index in the root symbol:


x^{(1)/(2)}=√(x)

In the case of this problem, ...


(S^2)^{(1)/(2)}=\left((3V)/(H)\right)^{(1)/(2)}\\\\S=\sqrt{(3V)/(H)}

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