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What is the equation, in point-slope form, of the line that is

perpendicular to the given line and passes through the
point (-4, 3)?
y-3 = -2(x + 4)
Y-3 = -
2(x+4)
y-3 = {(x + 4)
Y-3 = 2(x + 4)

User Ladislas
by
5.9k points

1 Answer

3 votes

Answer:

y=1/2x+5

Explanation:

the perpendicular line equation's slope is a negative reciprocal, so the new equation's slope is 1/2. so now you have y=1/2x+b plug in (-4,3) to find b. so you will do 3=1/2(-4)+b. 3=-2+b and then you solve for b. you would get b=5. so, the new equation is y=1/2x+5

User Idak
by
5.4k points