9.3k views
4 votes
What is the equation, in point-slope form, of the line that is

perpendicular to the given line and passes through the
point (-4, 3)?
y-3 = -2(x + 4)
Y-3 = -
2(x+4)
y-3 = {(x + 4)
Y-3 = 2(x + 4)

User Ladislas
by
8.5k points

1 Answer

3 votes

Answer:

y=1/2x+5

Explanation:

the perpendicular line equation's slope is a negative reciprocal, so the new equation's slope is 1/2. so now you have y=1/2x+b plug in (-4,3) to find b. so you will do 3=1/2(-4)+b. 3=-2+b and then you solve for b. you would get b=5. so, the new equation is y=1/2x+5

User Idak
by
7.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories