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A stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. What is the speed of the car? PLS HELP

User Rax
by
4.3k points

2 Answers

4 votes

Answer: 7.36m/s

Step-by-step explanation:

(Fo- f)/fo = 2v/c

1030/2.10 x 10^10 = 2v/ 3 x 10^10

4.905= 2v/3 x 10^10

Rearrange for v

V = ((1030/2.10 x 10^10) x (3x 10^10)) / 2

V = 7.36 ( right for acellus)

User Davis Herring
by
4.9k points
5 votes

Answer: V = 15 m/s

Step-by-step explanation:

As stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,

F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz

Using doppler effect formula

F = C/ ( C - V) × f

Where

F = observed frequency

f = source frequency

C = speed of light = 3×10^8

V = speed of the car

Substitute all the parameters into the formula

2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10

2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)

1.000000049 = 3×10^8/(3×10^8 - V)

Cross multiply

300000014.7 - 1.000000049V = 3×10^8

Collect the like terms

1.000000049V = 14.71429

Make V the subject of formula

V = 14.71429/1.000000049

V = 14.7 m/s

The speed of the car is 15 m/s approximately

User Oleksandr Dashkov
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4.3k points