Question

What is the equation of a line , in general form, that passes through points (-1,2) and (5,2)

Answer 1

y-2=0

Explanation:

In y=mx+b

m=(y2-y1)/(x2-x1) [2]

Or another way of thinking about it is rise over run.

define point (-1,2) as x1,y1

define point (5,2) as x2,y2

substitute into formula [2]

m=(2-2)/(5-(-1))

We know that 2-2=0 therefore the slope (m) is 0

y=0x+b

Or simply

y=b

to solve for b we substitute into the formula any of the points

2=b for y1

or 2=b for y2

b=2

therefore y=2

to convert it into general form make the equation equal 0

y-2=0