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How much heat is necessary to increase temperature of 4 kg water from 20 degree Celsius to 80 degree Celsius?

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Answer:

2.4 × 10⁵ cal

Step-by-step explanation:

Step 1: Given data

  • Mass of water (m): 4 kg
  • Initial temperature: 20°C
  • Final temperature: 80°C
  • Specific heat capacity of water (c): 1 cal/g.°C

Step 2: Convert the mass to grams

We will use the relationship 1 kg = 1,000 g.


4kg * (1,000g)/(1kg) = 4,000 g

Step 3: Calculate the change in the temperature


\Delta T = T_f - T_i = 80 \° C - 20 \° C = 60 \° C

Step 4: Calculate the heat required (Q)

We will use the following expression.


Q = c * m * \Delta T = (1cal)/(g. \° C) * 4,000 g * 60 \° C = 2.4 * 10^(5) cal

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