Answer:
Explanation:
Hello!
The objective is to test if the population mean of three-circle red-on-white sheds is equal to the four excavation sites.
To compare the population means you have to apply an ANOVA. For this test the variable of interest is
X: number of three-circle red-on-white sheds.
There is only one factor: "Site" with four treatments "I, II, III; IV"
H₀: μ₁= μ₂= μ₃= μ₄
H₁: At least one population mean is different.
α: 0.05

Df treatments: k-1= 4-1= 3 (k= nº of treatments)
Df errors: N-K= 21-4= 17 (N= total observations for all treatments)

p-value: 0.4723
Using the p-value approach the decision rule is:
p-value ≤ α, reject the null hypothesis.
p-value > α, do not reject the null hypothesis.
The p-value is greater than the level of significance, the decision is to reject the null hypothesis.
Using a 5% significance level, there is not significant evidence to reject the null hypothesis. Then you can conclude that the population mean three-circle red-on-white sherd count is equal to all the excavation sites.
I hope this helps!