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24 votes
Find an equation for the line that passes through the points (-6, 3) and (6, -6).

User Mote Zart
by
8.4k points

2 Answers

4 votes
slope=-9/12 = -3/4

y=mx+b y=-3/4x+b

3=-3/4(-6)+b

b=3+9/2=7.5

Equation is y=-0.75x+7.5
User Tomascharad
by
7.9k points
11 votes

Answer:


y = -(3)/(4)x-(3)/(2)

Explanation:

First, calculate the slope of the line:


m = (y_2-y_1)/(x_2-x_1)\\m = ((-6) - 3)/(6 - (-6))\\m = (-9)/(12)\\m = (-3)/(4)

Next, calculate the y-intercept:

Choose any point on the line.


(-6,3)

Solve for
b.


y = mx + b\\b = y - (mx)\\b = 3 - ((-3)/(4) * -6)\\b = 3 - (9)/(2)\\b = (-3)/(2)

Finally, create the equation:


y = -(3)/(4)x-(3)/(2)

User Jonthan
by
7.4k points

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