What is the difference 2x-3/3x^2-x+2/6x

Question

asked Oct 8, 2021 169k views

2 Answers

ThandoBhebhe · Answer 1 · 2021-10-14T17:10:49+0000

Answer: D

Explanation:

To find the difference, we want to make sure both denominators are equal.

((6x)(2x-3))/((6x)(3x^2)) -((3x^2)(x+2))/((3x^2)(6x))

Now that the denominators are equal, we can distribute and multiply out.

(12x^2-18x)/(18x^3) -(3x^3+6x^2)/(18x^3)

With the fractions multiplied out, we can actually put it into one large fraction.

(12x^2-18x-3x^3-6x^2)/(18x^3)

Let's subtract the top expression.

(-3x^3+6x^2-18x)/(18x^3)

This may seem like our final answer, but we can actually factor out an 3x in the numerator and denominator.

((3x)(-x^2+2x-6))/((3x)(6x^2))

With the 3x factored out, they cancel out because 3x/3x=1.

Our final answer is:

(-x^2+2x-6)/(6x^2)