Question

What is the difference 2x-3/3x^2-x+2/6x

Answer 1

Answer:D

Explanation:

Answer 2

Answer: D

Explanation:

To find the difference, we want to make sure both denominators are equal.

`((6x)(2x-3))/((6x)(3x^2)) -((3x^2)(x+2))/((3x^2)(6x))`

Now that the denominators are equal, we can distribute and multiply out.

`(12x^2-18x)/(18x^3) -(3x^3+6x^2)/(18x^3)`

With the fractions multiplied out, we can actually put it into one large fraction.

`(12x^2-18x-3x^3-6x^2)/(18x^3)`

Let's subtract the top expression.

`(-3x^3+6x^2-18x)/(18x^3)`

This may seem like our final answer, but we can actually factor out an 3x in the numerator and denominator.

`((3x)(-x^2+2x-6))/((3x)(6x^2))`

With the 3x factored out, they cancel out because 3x/3x=1.

Our final answer is:

`(-x^2+2x-6)/(6x^2)`