Question

Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, 0) left parenthesis, right parenthesis, B(6, 0) right parenthesis, C(6, 7) right parenthesis, and D(2, 7).

What is the area of rectangle ABCD?

Answer 1

28 units squared

Explanation:

It becomes a lot easier if you just try to plot the points on an axis, but i'll try to explain.

A and B are x-intercepts and the bottom two corners of the rectangle. C and D are the top two corners of the rectangle. Like any other case, to find the area, you need just two things:

1) height

2) width

To find the width:

Consider the distance between A and B - the bottom 2 corners. The coordinates are (2,0) and (6,0). Since we are trying to work out the width, just worry about the x-values. So, 6-2 = 4 and that is the width.

To find the height:

We'll take coordinates B and C - the bottom and top right corners of the rectangle. Coordinates are (6,0) and (6,7). Since we are trying to work out the height, just look at the y-values. So, 7 (top corner) - 0 (bottom corner) = 7, which is the height.

To figure out area:

Just multiply width by height, so:

4 x 7 = 28

And the area is 28 units squared. Change the units into whatever unit of measurement they give you (m, cm, mm etc.)

Hope this helped :)