203k views
4 votes
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, 0) left parenthesis, right parenthesis, B(6, 0) right parenthesis, C(6, 7) right parenthesis, and D(2, 7).

What is the area of rectangle ABCD?

User Matox
by
8.1k points

1 Answer

6 votes

Answer:

28 units squared

Explanation:

It becomes a lot easier if you just try to plot the points on an axis, but i'll try to explain.

A and B are x-intercepts and the bottom two corners of the rectangle. C and D are the top two corners of the rectangle. Like any other case, to find the area, you need just two things:

1) height

2) width

To find the width:

Consider the distance between A and B - the bottom 2 corners. The coordinates are (2,0) and (6,0). Since we are trying to work out the width, just worry about the x-values. So, 6-2 = 4 and that is the width.

To find the height:

We'll take coordinates B and C - the bottom and top right corners of the rectangle. Coordinates are (6,0) and (6,7). Since we are trying to work out the height, just look at the y-values. So, 7 (top corner) - 0 (bottom corner) = 7, which is the height.

To figure out area:

Just multiply width by height, so:

4 x 7 = 28

And the area is 28 units squared. Change the units into whatever unit of measurement they give you (m, cm, mm etc.)

Hope this helped :)

User Shobhakar Tiwari
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories