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A bag contains 9 marbles: 3 are green, 2 are red, 4 are blue. Yolanda chooses a marble at random, and without putting it back, chooses another one at random. What is the probability that the first marble is blue and the second is green?

User Hien Tran
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1 Answer

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Answer:
\bold{(1)/(6)=16.67\%}

Explanation:

First pick and Second pick


(4\ blue)/(9\ total\ marbles)*(3\ green)/(8\ remaining\ marbles)\quad =(12)/(72)\quad =\large\boxed{(1)/(6)}

User Waffles
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