Question

Two Vertical buildings 91 metres apart are136 metres and 192 metres high respectively. Find the angle of elevation form the top of the shorter building o the top of the taller building to the nearest degree

Answer 1

≈ 32°

Explanation:

Distance between buildings= 91 m

Elevation difference= 192 m- 136 m= 56 m

Right triangle ΔABC is formed by connecting 3 points, see attached

∠C is one to be calculated

tan C=AB/AC= 56/91

tan C= 0.62

∠C ≈ 32°

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∠B = (90°-32°)= 58° in case I misread which angle to be found