Question

Use a delta-star conversion to simplify the delta BCD (40 , 16 , and 8 ) in the

bridge network in Fig. f and find the equivalent resistance that replaces the network
between terminals A and B, and hence find the current I if the source voltage is 52 V.​

Answer 1

Current, I = 4A

Step-by-step explanation:

Since the connection is in delta, let's convert to star.

Simplify BCD:

`R1 = (40 * 8)/(40 + 16 + 8) = (320)/(64) = 5 ohms`

`R2 = (16 * 8)/(40 + 16 + 8) = (128)/(64) = 2 ohms`

`R3 = (40 * 16)/(40 + 16 + 8) = (640)/(64) = 10 ohms`

From figure B, it can be seen that 6 ohms and 6 ohms are connected in parallel.

Simplify:

`(6 * 6)/(6 + 6) = (36)/(12) = 3 \ohms`

Req = 10 ohms + 3 ohms

Req = 13 ohms

To find the current, use ohms law.

V = IR

Where, V = 52volts and I = 13 ohms

Solve for I,

`I = (V)/(R) = (52)/(13) = 4A`

Current, I = 4 A