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Each bag of Skittles is supposed to have at least 30 Skittles. A machine that fills bags has a 0.005 probability of under filling a bag. For every thousand bags, what is the standard deviation for the number of bags (out of a thousand) that are under-filled. Assume the Poisson distribution.

User Kdubs
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Answer:

The standard deviation for the number of bags that are underfilled is 2.236.

Explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:


P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)

In which

x is the number of sucesses

e = 2.71828 is the Euler number


\mu is the mean in the given interval. The variance is the same as the mean, which mean that the standard deviation is the square root of the mean.

In this question:

Expected number of underfilled bags in a sample of n bags is:


\mu = 0.005*n

1000 bags, so


\mu = 0.005*1000 = 5

Standard deviation
S = √(5) = 2.236

The standard deviation for the number of bags that are underfilled is 2.236.

User Luccas Clezar
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