Answer:
The half-life of the material is 2 years
Step-by-step explanation:
Given;
initial count rate = 2000 decays/minute
final count rate = 500 counts/min
decay time = Four hours
To determine the half life of the material; we create a simple decay table that matches the decay time and count rates.
time (years) count rate
0 2000 decays/minute
2 1000 decays/minute
4 500 decays/minute
Half life is the time intervals = 2 years
Also using a formula;
![N = (N_o)/((t/2)^2) \\\\N_o-is \ the \ initial \ count\ rate\\\\N-is \ the \ final \ count\ rate\\\\t/_2 - is \ the\ half\ life \\\\N = (N_o)/((t/2)^2) \\\\500 = (2000)/((t/2)^2)\\\\(t/_2)^2 = (2000)/(500) \\\\(t/_2)^2 = 4\\\\t/_2 = √(4) \\\\t/_2 = 2 \ years](https://img.qammunity.org/2021/formulas/chemistry/college/mzoyqx8inrw5a8boj24ohcivdsfhvh786p.png)
Therefore, the half-life of the material is 2 years