Question

Parallel light rays with a wavelength of 610nm fall on a single slit. On a screen 3.10m away, the distance between the first dark fringes on either side of the central maximum is 4.00mm.

What is the width of the slit?

Answer 1

The width of the slit will be ".946 mm".

Step-by-step explanation:

The given values are:

Wavelength = 610 × 10⁻⁹

Length, L = 3 m

As we know,

⇒
`(y)/(L) = (m(wavelength))/(a)`

On putting the estimated values, we get

⇒
`(2* 10^(-3))/(3.1) = ((1)(610 X 10^(-9)))/(a)`

On applying cross-multiplication, we get

⇒
`a=9.46* 10^(-4)`

⇒
`a = .946 mm`