Question

You have nitrogen gas (N2) at a pressure of 0.5 atm, a volume of 25000 mL, and a temperature of 300 K, how many grams of nitrogen are present?

Answer 1

About 7.109g

Step-by-step explanation:

25000mL is the same as 25 liters.

`PV=nRT \\\\0.5 (25)=n (0.0821) (300) \\\\n\approx 0.508`

Multiplying this by the molar mass of nitrogen, you get about 7.109 grams of nitrogen. Hope this helps!