Answer:
The average velocity of the object over the interval of time [2,6] is of 18 units of distance per unit of time.
Explanation:
The average velocity can be calculated as the division of the position change by the time change.
Find the average velocity of the object over the interval of time [2,6 ].
6 - 2 = 4 units of time (t, min,...)
s(6) = 141, s(2) = 69
141 - 69 = 72 units of distance(m, km...)
72/4 = 18 u.d./u.t.
The average velocity of the object over the interval of time [2,6] is of 18 units of distance per unit of time.