Question

What is the equation, in slope-intercept form, of the line that is perpendicular to the line

y-4 = -(x - 6) and passes through the point (-2, -2)?
o y = x - 10
0 y = x + 10
o y = 2 X-1
O y = x + 1

Answer 1

I think it is c

Explanation:

I just worked it out but I am not sure if I am 100% right.

hope this helped at all!!!

Answer 2

y = 3/2x - 1

Explanation:

Slope intercept form = y = mx + b

m = slope of the line = -2/3

y = -2/3x + b

Plug in (-2, -2) and the perpendicular line is

y = 3/2x - 1

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