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Provide the value of k: (2x-1)(kx+1)=6x^2-x-1
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5 votes
Provide the value of k:
(2x-1)(kx+1)=6x^2-x-1

User Frank Breitling
by
3.4k points

2 Answers

5 votes

Answer:

k= 6x-3/2x-1

Explanation:

User Santosh Shinde
by
4.3k points
4 votes

Answer:

k = 3

Explanation:

Expand the left side and compare the coefficients of like terms on both sides.

(2x - 1)(kx + 1) ← expand using FOIL

= 2kx² + 2x - kx - 1

Compare the coefficients of the x² term on both sides

2k = 6 ( divide both sides by 2 )

k = 3

User Invader Zim
by
4.1k points
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