Answer:
will ensure that accumulated amount at the end of one year is 1.5 times more than amount invested
Explanation:
Given: An amount was invested at r% per quarter.
To find: value of r such that accumulated amount at the end of one year is 1.5 times more than amount invested
Solution:
Let P denotes amount invested and n denotes time
As an amount (A) was invested at r% per quarter,
![A=P\left ( 1+(r)/(400) \right )^(4n)](https://img.qammunity.org/2021/formulas/mathematics/college/r8egrytrgj5v7kx38a5o3hp7qntew5bn48.png)
According to question, accumulated amount at the end of one year is 1.5 times more than amount invested.
So,
![A=1.5P+P=2.5P\\A=2.5P\\P\left ( 1+(r)/(400) \right )^(4n)=2.5P](https://img.qammunity.org/2021/formulas/mathematics/college/zj3mmm4szw0xtabino3a63h6tgi4toswhs.png)
Put n = 1
![P\left ( 1+(r)/(400) \right )^(4)=2.5P\\\left ( 1+(r)/(400) \right )^(4)=2.5\\1+(r)/(400) =(2.5)^{(1)/(4)}\\(r)/(100)=(2.5)^{(1)/(4)}-1\\r=100\left [ (2.5)^{(1)/(4)}-1 \right ]\\=25.7\%](https://img.qammunity.org/2021/formulas/mathematics/college/k2i4bd4u3dk7hx6q6vr9ibgocpg96nyvcw.png)