The point-slope form of the equation of the line that passes through (-9, -2) and (1, 3) is y– 3 = {(x - 1). What is the slope-intercept form of the equation for this line?

Question

asked Apr 4, 2021 144k views

2 Answers

Dykam · Answer 1 · 2021-04-10T23:24:37+0000

Answer:

y=(1)/(2)x+(5)/(2) .

Explanation:

If a line passing through two points, then the equation of line is

(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)

It is given that the passing through (1,3) and (-9,-2). So, equation of line in point slope form is

$\Rightarrow (y-3)=(-2-3)/(-9-1)(x-1)$

$\Rightarrow (y-3)=(1)/(2)(x-1)$

Slope intercept form of a line is

y=mx+b

where, m is slope and b is y-intercept.

Now,

(y-3)=(1)/(2)(x-1)

$\Rightarrow (y-3)=(1)/(2)(x}-(1)/(2)(1)$

$\Rightarrow y=(1)/(2)(x}-(1)/(2)+3$

$\Rightarrow y=(1)/(2)x+(5)/(2)$

Therefore, the required equation is
.