144k views
4 votes
The point-slope form of the equation of the line that passes through (-9, -2) and (1, 3) is y– 3 = {(x - 1). What is the

slope-intercept form of the equation for this line?

User Muhfred
by
8.0k points

2 Answers

3 votes

Answer:

The Answer is C

Explanation:

i think This is correct

User Blake Lockley
by
8.5k points
1 vote

Answer:


y=(1)/(2)x+(5)/(2).

Explanation:

If a line passing through two points, then the equation of line is


(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)

It is given that the passing through (1,3) and (-9,-2). So, equation of line in point slope form is


\Rightarrow (y-3)=(-2-3)/(-9-1)(x-1)


\Rightarrow (y-3)=(1)/(2)(x-1)

Slope intercept form of a line is


y=mx+b

where, m is slope and b is y-intercept.

Now,


(y-3)=(1)/(2)(x-1)


\Rightarrow (y-3)=(1)/(2)(x}-(1)/(2)(1)


\Rightarrow y=(1)/(2)(x}-(1)/(2)+3


\Rightarrow y=(1)/(2)x+(5)/(2)

Therefore, the required equation is
y=(1)/(2)x+(5)/(2).

User Dykam
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories