Answer:
the amount of alcohol to be added is 128 grams
Explanation:
Given that:
The initial mass of the hand sanitizer = 480 grams
The initial strength of the hand sanitizer = 24 %
The new strength of the hand sanitizer = 40%
The objective here is to determine the final amount of alcohol that is to be added to get the new strength of the alcohol
First; let's find the mass of alcohol in the initial hand sanitizer;
SO;
= 24 % of 480
![=(24)/(100)*480](https://img.qammunity.org/2021/formulas/mathematics/college/wum3b14h6jduit99hc47ogrp9136kwbr1d.png)
= 115.2 grams
If y should represent the mass of the alcohol added to have 40%; we have
The new amount of the alcohol to be
![(115.2 + y) \ grams](https://img.qammunity.org/2021/formulas/mathematics/college/zaregnbmeozhjh9ilgwegxmpl23e0vi4wr.png)
The new amount of the hand sanitizer will be
![(480 + y) grams](https://img.qammunity.org/2021/formulas/mathematics/college/a9c7sht90hqieoy4ld16im0lyz5zefyard.png)
∴
For the new strength of sanitizer:
40 % of (480 + y) = (115.2 + y)
![0.4 *(480 + y) = (115.2 + y) \\ \\ 192 + 0.4 y = 115.2 + y \\ \\ y (1 - 0.4) = 192 - 115.2 \\ \\ y= (76.8)/(0.6) \\ \\ y = 128 \ grams](https://img.qammunity.org/2021/formulas/mathematics/college/yg0neu3wuqmkhvneknxe7wrmm4hvl7pk14.png)
Thus ; we can conclude that the amount of alcohol to be added is 128 grams