Question

A scuba tank contains air at 2975 psi and 25°C. The tank is left in a car in the

hot sun and the temperature increases to 44°C. What will be the pressure (psi)
in the tank?

Answer 1

The new pressure is 3164.58 psi.

Step-by-step explanation:

We have,

Initial pressure,
`P_1= 2975\ psi`

Initial temperature,
`T_1=25^(\circ)=298.15\ K`

The tank is left in a car in the hot sun and the temperature increases to 44°C,
`T_2=44^(\circ) =317.15\ K`

Let
`P_2` is the final pressure in the tank. Gay Lussac's law,

`P\propto T\\\\(P_1)/(P_2)=(T_1)/(T_2)\\\\P_2=(P_1T_2)/(T_1)`

Plugging all the values,

`P_2=(2975* 317.15)/(298.15)\\\\P_2=3164.58\ psi`

So, the new pressure is 3164.58 psi.