Question

What are the x-intercepts
1. (x - 12) (x + 6) = 0​

Answer 1

`x=12,\:x=-6` are your x intercepts

Explanation:

`\left(x-12\right)\left(x+6\right)=0\\\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)\\\mathrm{Solve\:}\:x-12=0:\quad x=12\\x-12=0\\\mathrm{Add\:}12\mathrm{\:to\:both\:sides}\\x-12+12=0+12\\Simplify\\x=12\\\mathrm{Solve\:}\:x+6=0:\quad x=-6\\x+6=0\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\\x+6-6=0-6\\Simplify\\x=-6\\The\:solutions\:to\:the\:quadratic\:equation\:are:\\x=12,\:x=-6`

Answer 2

( x - 12 ) ( x + 6 ) = 0

x - 12 = 0 and x + 6 = 0

x = 12 and x = -6