Answer:
a. 0.15%
Explanation:
The Z-score of 940 pounds is ...
(X -µ)/σ = (940 -3550)/870 = -3
The empirical rule tells you that 99.7% of the normal distribution lies within Z = ±3. Half of the remaining 0.3% lies below Z = -3, which is the set of weights of interest.
The probability that a car weighs less than 940 lbs is about 0.15%.