Answer:
a. 16%
Explanation:
The difference from the mean is ...
(x - µ) = 4420 lb -3550 lb = 870 lb
Then the minimum Z-score of the traffic of interest is ...
(x - µ)/σ = (870 lb)/(870 lb) = 1
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The "empirical rule" tells you that 68% of a normal distribution is within 1 σ (Z = ±1) of the mean. If 68% is inside that range, then the remaining 32% is outside that range. The normal distribution is symmetrical about the mean, so half that quantity is below Z = -1, and the other half, 16%, is above Z=1.
About 16% of the cars have weights more than 4420 pounds.