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What is the height of this isosceles triangle?

What is the height of this isosceles triangle?-example-1

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Answer:

height ≈ 11.9 units

Explanation:

Construct a perpendicular bisector from the vertex to the base, thus splitting the triangle into 2 right triangles.

Using the sine ratio in one of these right triangles, then

sin48° =
(opposite)/(hypotenuse) ( the opposite is the height h )

sin48° =
(h)/(16) ( multiply both sides by 16 )

16 × sin48° = h , thus

h ≈ 11.9 ( to the nearest tenth )

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