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Solve the following equation 4×6x−7=1 x= log8log6 x= log2log6 x= log6log8 x= log6log2

User NLZ
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1 Answer

3 votes

Answer:

The value of x is
x=(\log(2))/(\log(6)).

Explanation:

Solve the equation as follows:


4* 6^(x)-7=1


4* 6^(x)=7+1


6^(x)=(8)/(4)


6^(x)=2

Take log on both sides.


\log(6^(x))=\log(2)


x\log (6)=\log(2)


x=(\log(2))/(\log(6))

Thus, the value of x is
x=(\log(2))/(\log(6)).

User Jrummell
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