Question

Ignore circled one and work it out please​

Answer 1

a.
`((x-7))/(x^2+x-30)`

Explanation:

`\huge (x^2-3x-28)/((x^2+10x+24)(x-5)) \\\\\huge {=(x^2-7x+4x-28)/((x^2+6x+4x+24)(x-5))}\\\\\huge {=\frac{x(x-7)+4(x-7)}{\{x(x+6)+4(x+6)\}(x-5)}}\\\\\huge {=((x-7)(x+4))/((x+6)(x+4)(x-5))}\\\\\huge {=((x-7))/((x+6)(x-5))}\\\\\huge {=((x-7))/(x^2+(6-5)x+6(-5))}\\\\\huge {=((x-7))/(x^2+x-30)}`