Question

In the circle, m BC = 94°. The diagram is not drawn to scale.

What is BCP
188
94
47
86

Answer 1

this is the diagram i need help too please

Answer 2

In the given circle with
`\(m\widehat{BC} = 94^\circ\)`, applying the chord-tangent angle theorem yields
`\(m\angle BCP = (94)/(2) = 47^\circ\)`, as the angle is half the intercepted arc.

In the circle,
`\(m\widehat{BC} = 94^\circ\)`.

Theorem Application:

Apply the theorem that states, "An angle formed by a chord and a tangent that intersect on a circle is half the measure of the intercepted arc."

Interpreting the Theorem:

In this context, the chord is
`\(\overline{BC}\)`, and the tangent is
`\(\overline{CP}\)`. The angle formed at B by this chord and tangent is
`\(m\angle BCP\)`.

Finding the Measure of
`\(m\angle BCP\)`:

According to the theorem,
`\(m\angle BCP\)` is half the measure of the intercepted arc, which is
`\(m\widehat{BC}\)`.

Calculation:

`\[m\angle BCP = \frac{m\widehat{BC}}{2} = (94)/(2) = 47^\circ\]`

Therefore, the measure of
`\(m\angle BCP\)` is
`\(47^\circ\)`, half of
`\(m\widehat{BC}\)`.

The complete question is:

In the circle,
`\(m\widehat{BC}\)`=94°. The diagram is not drawn to scale. What is
`\(m\angle BCP\)`?