![4!=4*3*2*1=24\\3!=3*2*1=6\\2!=2*1\\1!=1\\0!=?](https://img.qammunity.org/2021/formulas/mathematics/college/lib6fjj8auu7q3hpaqxfsyhisp3y5o0nmc.png)
Notice that when we go from 4! to 3! , we divide by 4.
(Because
the 4's cancel)
And when we go from 3! to 2! , we divide by 3, and etc.
We can use this pattern to see why 0! = 1.
![4!=4*3*2*1=24\\3! = 4!/4=24/4=6\\2!=3!/3=6/3=2\\1!=2!/2=2/2=1\\0!=1!/1=1/1=1](https://img.qammunity.org/2021/formulas/mathematics/college/m6gszhjsiuipd1th4zho4fvh7zg7oxu1ep.png)
And so by following the pattern, we determine that 0! = 1
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Note:
There are no factorials of negative numbers, and we can use the pattern to show why:
![0!=1\\-1!=0!/0=1/0=???!!??!?](https://img.qammunity.org/2021/formulas/mathematics/college/piic9wglnc4m8wh3blwfhs6p315qetfti0.png)
You can't divide a number by 0, therefore -1! doesn't exist, so -2! doesn't exist and so on. So you can't do the factorial of any negative number.
(Or at least there no real solutions to negative factorials)
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