Question

The equation of a circle is given below.

(x+12)^{2}+(y-9)^{2} = 35(x+12)
2
+(y−9)
2
=35left parenthesis, x, plus, 12, right parenthesis, squared, plus, left parenthesis, y, minus, 9, right parenthesis, squared, equals, 35
What is its center

Answer 1

The raidus is 5.92

Explanation:

Answer 2

Center is
`(-12,9)`

Explanation:

Given: Equation of a circle is
`(x+12)^2+(y-9)^2=35`

To find: center of the circle

Solution:

A circle is a locus of all points which are at equidistant from the fixed point (center).

Equation of a circle is of form
`(x-a)^2+(y-b)^2=r^2` where
`(a,b)` represents center of the circle and r denotes radius of the circle.

Given equation is
`(x+12)^2+(y-9)^2=35`

`\left [ x-(-12) \right ]^2+(y-9)^2=35`

Compare this equation with
`(x-a)^2+(y-b)^2=r^2`

Center is
`(a,b)=(-12,9)`