Question

Enter the equation of the circle with C(-7, 2) and containing the point P(-3,5).

A. r= V[(x-7)2 + (y + 2)2]
B. 5 = v[(x - 3)2 + (y + 5)21
C. 5 = V[(x +7)2 + (y-2)21
D. r= V[(x + 3)2 + (y - 5)21
​

Answer 1

c) Equation of the circle

`√((x+7)^2+(y-2)^2)=5`

Explanation:

Given center of the circle C(-7,2) and containing the Point P(-3,5)

C P = r

C P =
`\sqrt{(x_(2) -x_(1))^2+(y_(2) -y_(1) })^2 }`

C P =
`√((-3 -(-7))^2+(5 -2))^2 }`

C P =
`√(16+9) = 5`

The radius r = 5

The equation of the circle C(-7,2) and radius =5

`(x-h)^2+(y-k)^2 = (r)^2`

`(x-(-7))^2+(y-2)^2 = 25`